The resultant velocity is 40.3 m/s at 7.1 degrees north of west
Explanation:
Jason's motion is divided into two parts.
At first, he moves west with a speed of
[tex]v_x = 40.0 m/s[/tex]
Then, he moves north with a speed of
[tex]v_y = 5.0 m/s[/tex]
The two velocities are at right angle, so they form the sides of a right triangle, and the magnitude of the resultant velocity can be calculated using Pythagorean's theorem:
[tex]v=\sqrt{v_x^2+v_y^2}=\sqrt{40.0^2+5.0^2}=40.3 m/s[/tex]
And the direction can be found by using
[tex]\theta = tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.0}{40.0})=7.1^{\circ}[/tex]
So, 7.1 degrees north of west.
Learn more about vector addition here:
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