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Metals often form several cations with different charges. Cerium, for example, forms Ce3+ and Ce4+ ions, and thallium forms Tl+ and Tl3+ ions. Cerium and thallium ions react as follows: 2Ce4+(aq)+Tl+(aq)→2Ce3+(aq)+Tl3+(aq) This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn2+(aq) according to the following mechanism: Ce4+(aq)+Mn2+(aq)Ce4+(aq)+Mn3+(aq)Mn4+(aq)+Tl+(aq)→→ →Ce3+(aq)+Mn3+(aq)Ce3+(aq)+Mn4+(aq)Mn2+(aq)+Tl3+(aq) Part A What is the rate law for the uncatalyzed reaction?

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codedmog101

Answer:

Rate law for the uncatalyzed reaction:

Rate = k[Ce^4+]^2[Tl]

Explanation: rate law shows the mathematical relationship by comparing the rate of reaction with the reactants concentration.

Rate law= k[reactantA][reactantB] .

Rate law can be used to derive an equation that shows a reactant as a function of time. Also, it can be use to calculate the rate of reaction from known concentration.

pstnonsonjoku

Answer:

Rate of reaction= k [Ce^3+]^2 [Tl^3+]

Explanation:

Since the reaction is thought to occur in a single reaction step for the uncatalysed reaction, and the reaction equation is: 2Ce4+(aq)+Tl+(aq)→2Ce3+(aq)+Tl3+(aq)

Rate of reaction= k [Ce^3+]^2 [Tl^3+]

Note that the rate of reaction = rate of appearance of products or rate of disappearance of reactants as shown above.

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