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07-11-2019
Physics

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A 6kg rock is thrown vertically upward from the top of a cliff that is 28m high. It was thrown with a speed of 11ms . Calculate the greatest height of the rock as measured from the base of the cliff.

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sodiqolamilekan69 sodiqolamilekan69

08-11-2019

Answer:H=34.05m

Explanation: H=u²/2g+ 28m height of the cliff

u=11ms⁻¹

g=10ms⁻²

H=11²/2*10

H=121/20

H=6.05+28

H=34.05m

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