Zak, helping his mother rearrange the furniture in their living room, moves a 42.3 kg sofa 5.7 m with a constant force of 11 N. What is the work done by Zak on the sofa? Neglect friction. Answer in units of J. 011 (part 2 of 2) 10.0 points What is the average acceleration of the sofa?

Respuesta :

Answer:

W = 62.7 J

a = 0.26 m/s²

Explanation:

Work (W) is defined as the product of force( F) by the distance (d) the body travels due to this force.  

W= F*d Formula ( 1)

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

The component of the force that performs work must be parallel to the displacement.

Data

F = 11 N

d =  5.7 m

Work done by Zak on the sofa

We apply the Formula ( 1) :

W = (11 N )* (5.7 m)

W = 62.7 J

Average acceleration of the sofa

We apply Newton's second law to the sofa :

∑F = m*a Formula (2)

∑F : algebraic sum of the forces acting on the sofa (N)

m : mass  (kg)

a : acceleration  (m/s²)

Data : m= 42.3 kg , F= 11 N

We replace Data in the formula (2)

F = m*a

11  = (42.3)*a

a = (11) / (42.3)

a = 0.26 m/s²

The work done by Zak on the sofa =62.7J

The average acceleration of the sofa =0.26mls²

Calculation of work done and acceleration

The distance covered by the movement= 5.7m

The mass of the sofa = 42.3kg

The constant force applied = 11 N.

Formula for work done = Force× distance

= 11 × 5.7

= 62.7J

To calculate the acceleration,

Force= mass × acceleration

Make "acceleration" the subject of formula

acceleration = force/mass

= 11/42.5

= 0.2588

= 0.26mls²

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