Answer:
[tex]F_y=137.61N[/tex]
Explanation:
The force exerted by Beth, has components on the two axes of the xy plane, [tex]Fcos\theta[/tex] on the x axis and [tex]Fsin\theta[/tex] on the y axis, where [tex]\theta[/tex] is the angle formed by the rope with the horizontal and [tex]F[/tex] is the magnitude of the force. So, the magnitude of the upward component of the force acting on the stake, is the force component in the y axis:
[tex]F_y=(147.3N)sin(69.1^\circ)\\F_y=137.61N[/tex]
