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Help pls! Given the following system of equations: 2x + 6y = 12 4x + 3y = 15 Which action creates an equivalent system that will eliminate one variable when they are combined?
Multiply the second equation by −2 to get −8x − 6y = −30.
Multiply the first equation by 2 to get 4x + 12y = 24.
Multiply the second equation by −4 to get −16x − 12y = −60.
Multiply the first equation by −4 to get −8x − 24y = −48.

Respuesta :

calculista

Answer:

Multiply the second equation by −2 to get −8x − 6y = −30.

Step-by-step explanation:

we have

[tex]2x+6y=12[/tex] ----> first equation

[tex]4x+3y=15[/tex] ----> second equation

Solve by elimination

Multiply the second equation by -2 both sides

[tex]-2(4x+3y)=-2(15)[/tex]

[tex]-8x-6y=-30[/tex] ---> equivalent second equation

Adds first equation and the equivalent second equation

[tex]2x+6y=12\\-8x-6y=-30\\------\\2x-8x=12-30\\-6x=-18\\x=3[/tex]

Find the value of y

substitute the value of x in any of the equations

[tex]2(3)+6y=12[/tex]

[tex]6y=12-6[/tex]

[tex]y=1[/tex]

the solution of the system is the point (3,1)

Answer:

answer A multiply by the second equation by -2 to get -8x - 6y = -30

Step-by-step explanation:

i took this test this is the anwser

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