Answer:
(a) Electric force will be [tex]77.285\times 10^{-9}N[/tex]
(B) Velocity [tex]v=2.1522\times 10^6m/sec[/tex]
Explanation:
We have given that radius of the circular orbit [tex]r=0.546\times 10^{-10}m[/tex]
Charge on electron [tex]e=1.6\times 10^{-19}C[/tex]
(A) According to coulomb's law electric force between two charges is given by
[tex]F=\frac{kq}{r^2}[/tex]
So electric force [tex]F=\frac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.546\times 10^{-10})^2}=77.285\times 10^{-9}N[/tex]
We know that centripetal force is given by [tex]F=\frac{mv^2}{r}[/tex]
So [tex]\frac{9.11\times 10^{-31}\times v^2}{0.546\times 10^{-10}}=77.285\times 10^{-9}[/tex]
[tex]v=2.1522\times 10^6m/sec[/tex]
