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A boat with a horizontal tow rope pulls a water skier. She skis off to the side, so the rope makes an angle of 12.0 ∘ with the forward direction of motion. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Pushing a stalled car. Part A If the tension in the rope is 200 N, how much work does the rope do on the skier during a forward displacement of 320 m?

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Answer:

62.601kJ

Explanation:

We have a force with a horizontal component given by the angle of 15°. So wue can take this component to calculate the total work done, that is,

[tex]W_T = Fd(cos\theta)[/tex]

Our values are,

[tex]d=320m[/tex]

[tex]Angle = 12\°[/tex]

[tex]Force=200N[/tex],

Substituting in Work equation,

[tex]W_T = 200(320)(cos12)[/tex]

[tex]W_T = 62601.4J[/tex]

[tex]W_T = 62.601kJ[/tex]

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