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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H 2O (l) → Ca(OH) 2 (s) In a particular experiment, a 2.00-g sample of CaO is reacted with excess water and 2.14 g of Ca(OH) 2 is recovered. What is the percent yield in this experiment?

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joseaaronlara

Answer:

The answer to your question is:  81%

Explanation:

Data

CaO = 2 g

Ca(OH)₂ = 2.14 g

Reaction balanced

                     CaO  +  H₂O   ⇒   Ca(OH)₂

                     

Molecular mass

Calcium oxyde = 40 + 16 = 56 g

Calcium hydroxide = 40 + 2 + 32 = 74 g

Process

Rule of three

                               56 g of CaO --------------   74 g of Ca(OH)₂

                                 2 g  of CaO -------------   x

                                 x = (2 x 74) / 56

                                x = 2.64 g of Ca(OH)₂

Percent yield

                         % Yield = [tex]\frac{2.14}{2.64}  x 100[/tex]

                         % yield = 81                            

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