In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, but it is larger and softer. In one hit, the ball leaves the bat at 12m/s after being in contact with the bat for 2.0ms . Assume constant acceleration during the hit.
A. What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units. a =
b. What is the net force on the ball during the hit?
Express your answer to two significant figures and include the appropriate units.
F =

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Muscardinus Muscardinus · Answer 1 · 2019-11-08T10:16:26+01:00

Explanation:

It is given that,

Mass of the ball, m = 140 g = 0.14 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 12 m/s

Time of contact, [tex]t=2\ ms=2\times 10^{-3}\ s[/tex]

(a) Let a is the acceleration of the ball. It is equal to the rate of change of velocity. It is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{12-0}{2\times 10^{-3}}[/tex]

[tex]a=6000\ m/s^2[/tex]

(b) Let F is the net force on the ball during the hit. It is equal to the product of mass and acceleration. It is given by :

[tex]F=ma[/tex]

[tex]F=0.14\ kg\times 6000\ m/s^2[/tex]

F = 840 N

Hence, this is the required solution.