Answer:
Molecular formula of this compound is N2O5
Explanation:
From the given values,
Weight of Nitrogen = 4.04 g
Weight of Oxygen = 11.46 g
No. of moles of Nitrogen =[tex]$=\frac{weight}{Molecular\,weight} =\frac{4.04}{14} =0.288$[/tex]
No. of moles of Oxygen[tex]$=\frac{weight}{molecular\,weight} =\frac{11.46}{16.00}=0.716$[/tex]
Ratio in between the no. of moles [tex]$=0.716:0.288=2.48 \approx 2.5$[/tex]
Which indicates the empirical formula of the compound is[tex]$NO_{2.5}$[/tex]
The molecular formula of a compound should have integral values. Hence by multiplying with 2, we get [tex]$N_2O_5$[/tex]
