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Suppose a claim is that the average pulse rates of women is μ = 73 and we wish to test this against an alternative hypothesis that the mean is not equal to 73. For a sample size of n = 40 and the test statistic of t = 2.463, find the P-value for this scenario. Round the p-value to three decimal places and enter it here.

Respuesta :

Answer:

P = 0.018

Step-by-step explanation:

In this problem, the null and alterantive hypothesis are:

[tex]H_0: \mu=73\\H_1: \mu \ne 73[/tex]

If the sample has a size of n = 40, the degrees of freedom are 40-1 = 39.

If the value of the test statistic is t = 2.463, we can look up in a t-table to find the p-value. In this test, because the mean can be bigger than 73 or smaller than 73, we have to do a two-tailed test.

For a two-tailed test for t = 2.463 and df = 39, the P-value is P = 0.018.

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