solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3(4^-4 over 3^3)*3^3 Please help and PLEASE explain in steps how you got the answer.

Respuesta :

Answer:

  [tex]3^64^{11}[/tex]

Step-by-step explanation:

It appears you're trying to simplify ...

  [tex](3^{-2}4^{-5}5^0)^{-3}\cdot\dfrac{4^{-4}}{3^3}\cdot 3^3[/tex]

The final factor cancels the denominator of the fraction, so we have ...

  [tex]3^{(-2)(-3)}4^{(-5)(-3)-4}=3^64^{11}[/tex]

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The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)