Answer:
[tex]1.6949*10^6 m[/tex]
Explanation:
Our values are
[tex]d=2m[/tex]
[tex]v=354m/s[/tex]
We can find the time through
[tex]t=\frac{d}{v}[/tex]
[tex]t=\frac{2}{354}[/tex]
[tex]t=5.64*10^{-3}s[/tex]
The expression for the distance between the Earth and the spaceship is as follow:
[tex]d=ct[/tex]
Where c is Light speed, and t our previous time.
[tex]d= (3*10^8)(5.64*10^{-3})[/tex]
[tex]d= 1.6949*10^6m[/tex]
Therefore the distance between the Eath and the Spaceship is [tex]1.6949*10^6[/tex] m