The acceleration of the rocket is [tex]6.25 m/s^2[/tex]
Explanation:
The motion of the rocket is a motion at constant acceleration, so we can use the following suvat equation:
v = u + at
where
v is the final velocity of the rocket after a time t
u is the initial velocity
a is the acceleration
In this problem, we have:
u = 0 (the rocket starts from rest)
[tex]v=7.50 \cdot 10^2 m/s[/tex] is the final velocity of the shuttle
t = 2.00 min = 120 s is the time interval
Solving for a, we find the shuttle's acceleration:
[tex]a=\frac{v-u}{t}=\frac{7.50\cdot 10^2-0}{120}=6.25 m/s^2[/tex]
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