Respuesta :
Explanation:
It is given that,
Displacement of the delivery truck, [tex]d_1=3.2\ km[/tex] (due east)
Then the truck moves, [tex]d_2=2.45\ km[/tex] (due south)
Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :
[tex]d=\sqrt{d_1^2+d_2^2}[/tex]
[tex]d=\sqrt{3.2^2+2.45^2}[/tex]
d = 4.03 km
Let [tex]\theta[/tex] is the direction of the truck’s displacement from the warehouse from south of east.
[tex]\theta=tan^{-1}(\dfrac{2.45}{3.2})[/tex]
[tex]\theta=37.43^{\circ}[/tex]
So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.
