Answer
given,
height of the light house = 292 foot
angle of depression of ship = 36°
angle of elevation of plane = 20°
Assuming the height of the plane above tower be 'h'
now
for distance of ship
[tex]tan \theta = \dfrac{P}{B}[/tex]
[tex]tan 36^0 = \dfrac{292}{B}[/tex]
[tex]B = \dfrac{292}{0.727}[/tex]
B= 401. 9 ft
height of the plane
[tex]tan \theta = \dfrac{P}{B}[/tex]
[tex]tan 20^0 = \dfrac{h}{401.9}[/tex]
[tex]h = 401.9 \times 0.364[/tex]
h= 146.28 ft
height of plane from ground = 292 + 146.28
= 438.28 ft