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Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and then stops spinning it. The salad spinner rotates 6.00 more times before it comes to rest. Assume that the spinner slows down with constant angular acceleration. Part A What is the magnitude of the angular acceleration of the salad spinner as it slows down? Express your answer numerically in radians per second per second. View Available Hint(s)

Respuesta :

Answer:

α =  8π/3 rad/s²

Explanation:

Initial angular speed

ωi = 20 x 2π/5 = 8π rad/s          ( 1 rev = 2π)

If angular acceleration is constant then we can say that final speed can be given as

ω²f=ωi² + 2 α θ

α = Angular acceleration

θ= Number of revolution

Given that final speed is zero.

ωf= 0 and θ =2π x 6 = 12π rad

0²=(8π)² + 2 x α  x 12π

α = - 8π/3 rad/s²

So the magnitude of the Angular acceleration is 8π/3 rad/s²

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