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Puck 1 (0.5 kg) travels with velocity 80 m/s to the right when it collides with puck 2 (2 kg) which is initially at rest. After the collision, puck 1 moves with a velocity of -16 m/s. Assume that no external forces are present and therefore the momentum for the system of pucks is conserved. What is the final velocity (in m/s) of puck 2 after the collision?

Respuesta :

Answer:

[tex]v_2=24\ m/s[/tex]

Explanation:

It is given that,

Mass of puck 1, [tex]m_1=0.5\ kg[/tex]

Mass of puck 2, [tex]m_2=2\ kg[/tex]

Initial speed of puck 1, [tex]u_1=80\ m/s[/tex]

Initial speed of puck 2, [tex]u_2=0\ m/s[/tex]

After the collision, the speed of puck 1, [tex]v_1=-16\ m/s[/tex]

Let [tex]v_2[/tex] is the final velocity (in m/s) of puck 2 after the collision. Using the conservation of momentum as :

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

[tex]0.5\times 80+2\times 0=0.5\times (-16)+2v_2[/tex]

[tex]v_2=24\ m/s[/tex]

So, the final velocity of the puck 2 after the collision is 24 m/s. Hence, this is the required solution.

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