Answer:
Explanation:
given,
space ship speed = 3 x 10³ m/s
distance travel in straight line = 5.56 x 10¹¹ m
speed at that point = 4 x 10⁴ m/s
a) acceleration
v² - u² = 2 a s
(4 x 10⁴)² - (3 x 10³)² = 2 x a x 5.56 x 10¹¹
[tex]a = \dfrac{0.01591\times 10^{11}}{11.12 \times 10^{11}}[/tex]
a = 1.43 x 10⁻³ m/s²
b) time require to travel mars
v + u = a t
4 x 10⁴ + 3 x 10³ = (1.43 x 10⁻³) t
t = 30069930 sec
[tex]t = \dfrac{30069930\ sec}{86400}\ days[/tex]
t = 348 days
