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What is the solution set of the equation 2z+6/z+2 = 3 − 1/z ?

Note: z ≠ 0, −2



{−1, 2}

{2, 1}

{2}

{−1}

Respuesta :

your answer is B the second one!

Answer:

{−1}

Step-by-step explanation:

First we need to specify that the equation given is wrong, it's misspelled, because that equation doesn't have solutions in the Real Numbers.

So, the equation must be expressed like this:

[tex]\frac{2z+6}{z} +2=\frac{3-1}{z}[/tex]

Now, we solve for z:

[tex]\frac{2z+6+2z}{z} =\frac{2}{z}\\ 4z+6=2\\4z=2-6\\4z=-4\\z=\frac{-4}{4} \\z=-1[/tex]

Therefore, the solution set of the equation is the last one.

PD: It's very important to write properly the equations give, otherwise all procedure would be wrong.