Answer:
the capacitor voltage is V = 20 V
Explanation:
Given,
Capacitance of the capacitor = 2.0 μF
energy stored = 200 W
time (t) =2.0 μs
Capacitor voltage = ?
[tex]\dfrac{dE}{dt}=200 W[/tex]
[tex]E =200\times 2 \times 10^{-6}[/tex]
[tex]E =400 \times 10^{-6}\ J[/tex]
we know,
[tex]E = \dfrac{1}{2}CV^2[/tex]
[tex]V =\sqrt{\dfrac{2E}{C}}[/tex]
[tex]V =\sqrt{\dfrac{2\times 400 \times 10^{-6}}{2\times 10^{-6}}}[/tex]
[tex]V =\sqrt{400}[/tex]
V = 20 V
so , the capacitor voltage is V = 20 V
