Our values are,
[tex]V= 4.90*10^6 m/s[/tex]
B = 0.240 T
θ= 61°
[tex]q = 1.6*10^{-19} C[/tex]
Where
V = Proton travels with a speed
B=Magnitude of magnetic field
θ=Angle
q=charge of proton
a)
Magnitude of the magnetic Force is given by,
[tex]F = q v Bsin\theta[/tex]
[tex]F = (1.6*10^{-19}C)* (4.90*10^6 m/s) * (0.240T) * sin(61)[/tex]
[tex]F= 1.54*10^{-13} N[/tex]
b ) Protons Accelerationis is given from Second Newton's law,
[tex]a = \frac{F}{m}[/tex]
[tex]m_{proton}=1.67*10-27 kg[/tex]
[tex]a = \frac{1.54*10-13 N}{1.67*10^{-27}kg}[/tex]
[tex]a= 9.2215*10^{13}m/s^2[/tex]
The magnitude of the magnetic force on this proton is equal to 1.54 × 10⁻¹³ Newton and its acceleration is equal to 9.22 × 10¹³ m/s².
Given the following data:
Speed = 4.90 × 10⁶ m/s.
Angle = 61°
Magnetic field = 0.240 T.
Mathematically, the magnitude of a magnetic force acting in a magnetic field is calculated by using this formula:
F = qvBsinθ
Where:
Substituting the given parameters into the formula, we have;
F = 1.6 × 10⁻¹⁹ × 4.90 × 10⁶ × 0.240 × sin61
F = 1.54 × 10⁻¹³ Newton.
Acceleration = force/mass
Acceleration = 1.54 × 10⁻¹³/1.67 × 10⁻²⁷
Acceleration = 9.22 × 10¹³ m/s².
Read more on magnetic field here: https://brainly.com/question/7802337
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