Answer:
b. cosine t less than 0 and cotangent t greater than 0
Step-by-step explanation:
We have the following relation
[tex]\frac{\pi }{2} < t <\pi[/tex]
if we apply the cosine function in the relation we get:
[tex]cos\frac{\pi }{2} <cost<cos\pi[/tex]
[tex]-1<cost<0[/tex]
the cosine of t is between 0 and -1 then (cosine t less than 0)
If we now apply cotangent function in the relation:
[tex]cotan\frac{\pi }{2} <cotan(t)<cotan\pi[/tex]
[tex]0 <cotan(t)<\infty[/tex]
This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0
