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As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed increases by a factor of 4.00 and the total cross-sectional area of the venules is 10.0cm2, what is the total cross-sectional area of the capillaries feeding these venules?

Respuesta :

Answer:

[tex]A_2 = 2.5\ cm^2[/tex]

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

[tex]\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}[/tex]

[tex]\dfrac{10}{A_2} =4[/tex]

[tex]\dfrac{10}{4} =A_2[/tex]

[tex]A_2 = 2.5\ cm^2[/tex]

hence, the area of capillaries is equal to 2.5 cm₂

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