Answer
given,
mass of pellet = 4.97 g
the compression distance = 3.90 cm = 0.039
Force to compress the spring = 9.12 N
we know,
F = k x
9.12 = k x 0.039
k = 233.85 N/m
conservation of energy:
[tex]\dfrac{1}{2}k x^2 = m g x + \dfrac{1}{2}mv^2[/tex]
[tex]\dfrac{1}{2}\times 233.85 \times 0.039^2 = 0.00497 \times 9.81 \times 0.039 + \dfrac{1}{2}\times 0.00497 \times v^2[/tex]
[tex]0.1778 = 0.0019 + 0.002485 v^2[/tex]
v = 8.41 m/s
b) conservation of energy:
[tex]\dfrac{1}{2}k x^2 = m g h[/tex]
[tex]\dfrac{1}{2}\times 233.85 \times 0.039^2 =0.00497\times 9.81 \times h[/tex]
[tex]h = 3.64\ m[/tex]
