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During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 57.0 kg and its horizontal component of velocity is 8.00 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball

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Answer:

3.73m/s

Explanation:

For a collision, the momentum will be

[tex]m_1v_1+m_2v_2 = (m_1+m_2)v'[/tex]

Where [tex]m_1[/tex] is the mass of ball

[tex]m_2[/tex] is the mass of perfomer

[tex]v_1[/tex] is the velocity of ball

[tex]v_2[/tex] is the velocity of performer

[tex]v'[/tex] is the velocity after collision.

Replacing we have,

[tex]m_1 = 57kg[/tex]

[tex]m_2 = 65kg[/tex]

[tex]v_1 = 8m/s[/tex]

[tex]v_2 = 0[/tex]

Then,

[tex]57)(8)+(65)(0)=(10+65)v'[/tex]

[tex]v' = \frac{(57)(8)}{(57+65)}[/tex]

[tex]v' = 3.73m/s[/tex]

Therefore, the recoil velocity is 3.73m/a

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