Given a polynomial and one of its factors find the remaining factors of the polynomial some of the factors may not be binomials 16x3-48x2-49x+147;x-3

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Answer:

The other factors are (4x + 7) and (4x - 7).

Step-by-step explanation:

One of the factor of the polynomial [tex]16x^{3} - 48x^{2} - 49x + 147[/tex] is given to be (x - 3). We have to find the other factors of this polynomial.

Now, [tex]16x^{3} - 48x^{2} - 49x + 147[/tex]

= [tex]16x^{2} (x - 3) - 49(x - 3)[/tex]

= [tex](x - 3)( 16x^{2} - 49)[/tex]

= [tex](x - 3)[(4x)^{2} - 7^{2}][/tex]{Since we know the formula, [tex](a^{2}-b^{2} ) = (a + b)(a - b)[/tex]}

= [tex](x - 3)(4x + 7)(4x - 7)[/tex]

Therefore, the other factors are (4x + 7) and (4x - 7). (Answer)