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Consider a solenoid of length L, N windings, and radius b (L is much longer than b). A current I is flowing through the wire. If the radius of the solenoid were doubled (becoming 2b), and all other quantities remained the same, the magnetic field inside the solenoid would A. would remain the same.

B. would become twice as strong.

C. would become one half as strong.

Respuesta :

cjmejiab

Answer:

A.

Explanation:

The equation of Magnetic Field is given by

[tex]B= \frac{\mu_0 NI}{L}[/tex]

Where

[tex]L= Lenght[/tex]

[tex]N =[/tex]Number of loops

I= current

[tex]\mu_0 =[/tex]constant of permeability of free space

As you can note, the magnetic field does not depend upon radius of the solenoid, therefore it would remain in same

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