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A metal alloy bolt is initially at 100.0°C. It is dropped into a coffee cup calorimeter containing 50.0 g of water at a temperature of 20.0°C. After stirring, the final temperature of both bolt and water is 25.0°C. Assuming no heat losses, and that the specific heat (capacity) of water is 4.18 J/(g ∙ K), what is the heat capacity of the bolt in J/K?

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Answer:

the heat capacity of the bolt is 13.9 J/K

Explanation:

J/K is short of " joule per kelvin", is the international system unit of heat capacity

heat energy = (mass of substance)(specific heat)(change in temperature)

Q = mc∆T

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat (units J/kg∙K)

∆ is a symbol meaning "the change in"

∆T = change in temperature (Kelvins, K)

Heat gained by water = heat lost by copper  = Q = mC∆T = (50 g)(4.18 J/g/deg)(5 deg) = 1045 J   = C x ∆T

C = 1045 J/75 = 13.9 J/deg

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