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Use the strategy for solving word problems, translating from the verbal conditions of the problem to a linear inequality. You are choosing between two telephone plans. Plan A has a monthly fee of $15 with a charge of $0.08 per minute for all calls. Plan B has a monthly fee of $3 with a charge of $0.12 per minute for all calls. How many calling minutes in a month make plan A the better deal?

Respuesta :

Answer: The plan A would be better deal for more than 300 calling minutes.

Step-by-step explanation:

Since we have given that

Plan A has a monthly fee of $15 with a charge of $0.08 per minute for all calls

Let the number of minutes be 'x'.

So, Equation would be

[tex]15+0.08x[/tex]

Plan B has a monthly fee of $3 with a charge of $0.12 per minute for all calls.

So, Equation would be

[tex]3+0.12x[/tex]

We need to find the number of calling minutes in a month to make plan A the better deal.

[tex]15+0.08x>3+0.12x\\\\15-3>0.12x-0.08x\\\\12>0.04x\\\\\dfrac{12}{0.04}>x\\\\300>x[/tex]

Hence, the plan A would be better deal for more than 300 calling minutes.

Manetho

Answer:

300<m

therefore, the number of minutes should be more than 300

Step-by-step explanation:

take cost of plan A as A

and Cost of plan B as B

Then,

A= 15+ 0.08 m

B= 3+0.12 m

where m is number of minutes talked per month

For  Plan A to be  a better deal, its cost should be

less than plan B

then,

A<B

15+ 0.08 m< 3+0.12 m

12<0.04 m

300<m

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