Answer:
[tex]q =1.07 \times 10^{-7}\ C [/tex]
Explanation:
given.
Two flat 4.0 cm × 4.0 cm electrodes carrying equal charge
space between the charges = 2 mm
Electric field strength = 7.6 x 10⁶ N/C
ε ₀ = 8.85 × 10⁻¹² C²/N · m²
magnitude of charge =?
Electric field strength between to two plates
[tex]E = \dfrac{q}{A\epsilon_0}[/tex]
[tex]q = E A \epsilon_0[/tex]
[tex]q = 7.6 \times 10^6 \times 0.04 \times 0.04 \times 8.85 \times 10^{-12}[/tex]
[tex]q =1.07 \times 10^{-7}\ C [/tex]