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Construct the 95% confidence interval for the population mean using the appropriate distributions. a. A random sample of 50 people’s body mass index has a mean of 27.7 and a standard deviation of 6.12. b. The average yards per carry among all NFL

Respuesta :

Answer: 95% confidence interval would be (26.01,29.39).

Step-by-step explanation:

Since we have given that

n = 50

Mean = 27.7

Standard deviation = 6.12

We need to construct 95% confidence interval for the population.

so, z = 1.96

So, it becomes,

[tex]\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)[/tex]

Hence, 95% confidence interval would be (26.01,29.39).

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