Answer:
620.71 L the final volume of the balloon.
Explanation:
Initial volume of the gas in the balloon= [tex]V_1=3.50 L[/tex]
Initial pressure of the gas in the balloon= [tex]P_1=1.20 atm[/tex]
Initial temperature of the gas in the balloon= [tex]T_1=18^oC =291.15 K[/tex]
Moles of gases = n
[tex]n=\frac{P_1V_1}{RT_1}[/tex]...[1]
Final volume of the gas in the balloon = [tex]V_2=3.50 L[/tex]
Final pressure of the gas in the balloon = [tex]P_2=5.70\times 10^{-3} atm[/tex]
Final temperature of the gas in the balloon = [tex]T_2=-45^oC =228.15 K[/tex]
Moles of gases = n
[tex]n=\frac{P_2V_2}{RT_2}[/tex]...[2]
[1] = [2]
[tex]\frac{P_2V_2}{RT_2}=\frac{P_1V_1}{RT_1}[/tex]
[tex]V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}[/tex]
[tex]V_2=\frac{1.29 atm \times 3.50 L\times 228.15 K}{5.70\times 10^{-3} atm\times 291.15 K}=620.71 L[/tex]
620.71 L the final volume of the balloon.