Answer:
The required probability is 0.0004995
Step-by-step explanation:
Consider the provided information
There are 14 horses and one person owns 5 of those horses.
We need to find the number of ways in which 5 horses finish first, second , third, fourth, and fifth.
Each horse has the same probability of winning,
Therefore, the required probability is:
The probability that one of those 5 horses will be first is [tex]\frac{5}{14}[/tex]
Now we have 4 horses left,
Probability that out of remaining 4 horses one will be second is [tex]\frac{4}{13}[/tex].
The probability that out of remaining 3 horses one will be third is [tex]\frac{3}{12}[/tex].
The probability that out of remaining 2 horses one will be fourth is [tex]\frac{2}{11}[/tex].
The probability that out of remaining 1 horses one will be fifth is [tex]\frac{1}{11}[/tex].
Hence, the total probability is:
[tex]\frac{5}{14}\times \frac{4}{13} \times \frac{3}{12} \times \frac{2}{11}\times \frac{1}{10}=0.0004995[/tex]
Hence, the required probability is 0.0004995
