Answer:
The 95% confidence interval for the mean life expectancy of non-hispanic white males is (73.3 years, 79.3 years).
Step-by-step explanation:
This is the 95% confidence interval for the mean life expectancy of non-hispanic white males.
Our sample size is 100
The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So
[tex]df = 100-1 = 99[/tex]
Then, we need to subtract one by the confidence level [tex]\alpha[/tex] and divide by 2. So:
[tex]\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025[/tex]
Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.025 in the two-sided t-distribution table, we have [tex]T = 1.984[/tex]
Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So
[tex]s = \frac{15}{\sqrt{100}} = 1.5[/tex]
Now, we multiply T and s
[tex]M = T*s = 1.984*1.5 = 2.976[/tex]
Then
The lower end of the confidence interval is the mean subtracted by M. So:
[tex]L = 76.3 - 2.976 = 73.3[/tex]
The upper end of the confidence interval is the mean added to M. So:
[tex]L = 76.3 + 2.976 = 79.3[/tex]
The 95% confidence interval for the mean life expectancy of non-hispanic white males is (73.3 years, 79.3 years).