Answer:
366.6J
Explanation:
We only need to apply conservative linear momentum, making v the initial speed of pigeon, so
[tex]m_1v_1+m_2v_2 = (m_1+m_2)V[/tex]
[tex]600g*88m/s+458g*v_2 = (600+458)*65m/s[/tex]
Solving for v,
[tex]v_2 = 34.87m/s[/tex]
The energy lost we can calculate with
[tex]KE_{lost} = \frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2-\frac{1}{2}(m_1+m_2)V^2[/tex]
[tex]KE_{lost} = \frac{1}{2}*0.6*88^2 + \frac{1}{2}*0.458*34.87^2 - \frac{1}{2} (0.6+0.458)*65^2[/tex]
[tex]KE_{lost} = 366.6J[/tex]