Please help me answer for 29, 30, 31 please

Answer:
29. [tex]f(10) = 0.0078[/tex]
30. [tex]f(5)=40.5[/tex]
31. [tex]f(2)=6[/tex]
Step-by-step explanation:
Question 29:
Given:
[tex]f(n)=4\times (\frac{1}{2})^{n-1}[/tex]
Plug in 10 for n. This gives,
[tex]f(10)=4\times (\frac{1}{2})^{10-1}\\f(10)=4\times (\frac{1}{2})^{9}=0.0078[/tex]
Therefore, the tenth term is 0.0078.
Question 30:
Given:
[tex]f(n)=\frac{1}{2}\times 3^{n-1}[/tex]
Plug in 5 for n. This gives,
[tex]f(5)=\frac{1}{2}\times 3^{5-1}=\frac{1}{2}\times 3^4=\frac{1}{2}\times 81=40.5[/tex]
Therefore, the fifth term is 40.5.
Question 31:
Given:
[tex]f(1)=2, f(n)=f(n-1)+4[/tex]
Plug in 2 for n. This gives,
[tex]f(2)=f(1) + 4\\f(2)=2+4=6[/tex]
Therefore, the second term is 6.