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10. A frog leaps from its resting position at the
lake's bank onto a lily pad. If the frog has a
mass of 0.5 kg and the acceleration of the leap
is 3 m/s2, what is the force the frog exerts on
the lake's bank when leaping?
a. 0.2 N
b. 0.8 N
C. 1.5 N
d. 6.0 N

Respuesta :

Force = mass(m) ×acceleration(a)

m=0.5 kg

a= 3 m/s2

F = 0.5 × 3 = 1.5N.

What is force?

Force is energy exert that can influence a change in the motion of an object.

When force is applied it can cause an object to move and also shift it's location from a place to another.

Force = mass(m) ×acceleration(a)

m=0.5 kg

a= 3 m/s2

F = 0.5 × 3 = 1.5N.

Therefore, Force= 1.5N.

Learn more on force here,

https://brainly.com/question/12785175

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Option C) 1.5N is the correct answer.

Hence, the force exerted on the lake by the frog is 1.5 Newtons.

Given the data in the question;

  • Mass of frog; [tex]m = 0.5kg[/tex]
  • Acceleration; [tex]a = 3m/s^2[/tex]
  • Force exerted by the frog; [tex]F = \ ?[/tex]

Newton’s 2nd Law of Motion

Newton’s 2nd Law of Motion states that force equals to the rate of change of momentum. i.e force equals mass multiply by acceleration.

This expressed as;

[tex]F = m * a[/tex]

To determine the force exerted on the lake by the frog, we substitute our given values into the expression above:

[tex]F = m * a\\\\F = 0.5kg * 3m/s^2\\\\F = 1.5kgm/s^2\\\\F = 1.5N[/tex]

Option C) 1.5N is the correct answer.

Hence, the force exerted on the lake by the frog is 1.5 Newtons.

Learn more about Newton's Second law: https://brainly.com/question/13787679

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