4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.
Solution:
We will start with the Molarity
[tex]\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }[/tex]
Also we know 1000 ml = 1 L
Therefore 37.5 ml by 1000ml we obtained 0.0375L
Equation for solving mole of solute
[tex]\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }[/tex]
Now, multiply 0.750M by 0.0375
Substitute the known values in the above equation we get
[tex]0.750 \times 0.0375=0.0281[/tex]
Also we know that Molar mass of KI is 166 g/mol
So divide the molar mass value to get the no of grams.
[tex]0.028 \times 166=4.648[/tex]
So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.
