If you have 10 red balls, you have blue balls in proportion 3:2, so you have 15 blue balls. Moreover, you have white balls in proportion 8:2=4:1, so you have 40 white balls.
Removing 10 white and blue balls causes you to have 30 white, 10 red and 5 blue balls.
Since 30=5*6 and 10=5*2, the new proportion of white, red and blue balls is 6:2:1.
The new ratio of the white, blue and red balls in the bag is 6:1:3
We are given the ratio of balls. We can assume the counts of the real amount of those balls by taking them as some multiple of given ratio, but the multiple will be common for all counts since in ratio, we cancel out equal factors.
Let the balls in bag be as follows:
8x white ball, 3x blue balls and 2x red balls.
Since it is given that there are 10 red balls, thus we have:
[tex]2x = 10\\x = 5[/tex]
Or number of white ball is given is 8 times 5 = 40
number of blue balls = 3 times 5 = 15
Now 10 balls are removed of each color, thus new number of balls is:
number of white balls remaining = 40 - 10 = 30
number of blue balls remaining = 15 - 10 = 5
Thus the new ratio is given by:
white balls: blue balls: red balls = 30:5:15 = 6:1:3
Thus, the new ratio of the white, blue and red balls in the bag is 6:1:3
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