Answer:
1. £ 253,628.16
2. £ 350
3. 600,000 tickets
Step-by-step explanation:
1.
We will use compound growth formula for this, the formula is:
[tex]F=P(1+r)^t[/tex]
Where
F is future amount (what we want to find after 2 yrs)
P is present amount (240,000)
r is the rate of increase (2.8% = 2.8/100 = 0.028)
t is the time in years (t = 2 given)
Substituting, we get our answer:
[tex]F=P(1+r)^t\\F=240,000(1+0.028)^2\\F=240,000(1.028)^2F=253,628.16[/tex]
The house would be worth £253,628.16 after 2 years
2.
After the discount of 15%, he paid 297.50. So we can say:
What number, discounted by 15%, makes 297.50?
We can let that original price be "x" and write the equation as:
[tex]x-0.15x=297.50\\0.85x=297.50\\x=\frac{297.50}{0.85}\\x=350[/tex]
Originally, the laptop was worth £ 350
3.
480,000 is 80% of the total number of tickets.
If we let total number of tickets be t, we can say:
480,000 is 80% (80/100 = 0.8) of WHAT NUMBER (t)??
Now, we can write an algebraic equation and solve:
[tex]480,000=0.8t\\t=\frac{480,000}{0.8}\\t=600,000[/tex]
The total number of tickets available was 600,000 tickets
