Point Q' is the image of Q(-7,-6) under the translation (x, y) + (x+12, y +8).
What are the coordinates of Q'?
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Answer:

Step-by-step explanation:

the translation is : (x', y') = (x+12, y +8)

x' =x+12 and y'= y+8

you have : x = -7 and y = -6

so : x' = - 7+12 = - 5   and   y' = -6+8= 2

the cordinateurs of Q'(- 5 ; 2)

The co-ordinates of Q' is (5,2).

What is translation?

Translation means the displacement of a figure or a shape from one place to another. In translation a figure can move upward, downward, vertical and horizontal.

Now the given Pre-image point is Q(-7,-6)

To find the coordinates of Image point Q' after following translation.

Translation rules:

(x,y) ⇒ (x+12, y +8)

Now the Horizontal shift is given as-

(x,y) ⇒ (x+k, y )

when k>0  the point is translated k units to the right.

when k<0  the point is translated k  units to the left.

and the Vertical shift is given as-

(x,y) ⇒ (x, y +k)

when k>0  the point is translated k units up.

when k<0  the point is translated k  units down.

Now, the given translation (x,y) ⇒ (x+12, y +8) shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'= (x,y) ⇒ (-7+12, -6 +8)

Q'= (5,2)

So, the co-ordinates of Q' is (5,2).

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