The ages of each relative are 30, 10 and 80 years respectively.
Translating the word problem into an algebraic expression, we have;
[tex]J + D + P = 120[/tex] ......equation 1
[tex]J = 3D[/tex] .......equation 2
[tex]P = 2(J + D)[/tex] ......equation 3
Substituting eqn 2 and 3 into eqn 1, we have;
[tex]3D + D + 2J + 2D = 120\\\\6D + 2(3D) = 120\\\\6D + 6D = 120\\\\12D = 120\\\\D = \frac{120}{12}[/tex]
Dan, D = 10 years
For James;
[tex]J = 3(10)[/tex]
James, J = 30 years.
For Paul;
[tex]P = 2(J + D)[/tex]
[tex]P = 2(30 + 10)\\\\P = 2(40)[/tex]
Paul, P = 80 years.
Therefore, the ages of each relative are 30, 10 and 80 years respectively.
Read more: https://brainly.com/question/6463206
