Answer:
A, C, D
Step-by-step explanation:
Consider right triangles PQS, PRQ and QRS. In these triangles,
[tex]m\angle QPS=m\angle QPR=m\angle SQR\\ \\m\angle QSR=m\angle PQR=m\angle QSR[/tex]
So, by AA theorem,
[tex]\triangle PQS\sim \triangle PRQ\sim \triangle QRS[/tex]
From this statement, strictly follow options A and D
[tex]\triangle PQR\sim \triangle PSQ\\ \\\triangle PQS\sim \triangle QRS[/tex]
Option B is false, because PRS is not a triangle
Option C is true, because
[tex]\triangle PRQ\sim \triangle QRS\Rightarrow \triangle PQR\sim \triangle QSR[/tex]
