Answer:
[tex]3.35 * 10^{-6}V[/tex]
Explanation:
Our values are given by,
[tex]N = 8.75[/tex] flips per second
[tex]d_1 = 5.05 * 10 ^ {2}m[/tex]
B = 30.5 µT
Directly through the number of flips we can find the angular velocity, that is,
[tex]\omega = 2 \ piN[/tex]
[tex]\omega = 2 \pi (8.75) = 54.97rad / s[/tex]
On the other hand, for the production of the electromotive force it is necessary to resort to the equation that relates to the magnetic field, angular velocity and area. The equation is given by,
[tex]e = BA \omega[/tex]
Where,
B = magnetic field
A = Area
[tex]\omega =[/tex]Angular Velocity
In this way,
[tex]Area = (\pi / 4) * (5.05 * 10^{-2})^2 = 2.002 * 10^{-3} m2[/tex]
Applying the formula to find the emf, we replace,
[tex]e = BA\omega[/tex]
[tex]e = (30.5 * 10^{-6}) * (2.002 * 10^{-3}) * (54.97) = 3.35 * 10^{-6}V[/tex]
