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Suppose you are spinning a child around in a circle by her
arms. The radius of her orbit around you is 1 meter. Her speed
is 1 m/s. Her mass is 25 kg. The magnitude and direction of
tension in your arms is___N towards her.

Respuesta :

MathPhys

Answer:

25 N

Explanation:

Sum of the forces on the child in the radial direction:

∑F = ma

T = m v² / r

T = (25 kg) (1 m/s)² / (1 m)

T = 25 N

Cricetus

The direction of tension is "25 N" towards her.

Given values are:

Mass,

  • m = 25 kg

Velocity,

  • v = 1 m/s

Radius,

  • r = 1 m

As we know the formula,

→ [tex]T = \frac{mv^2}{r}[/tex]

By substituting the values, we get

→     [tex]= \frac{(25)(1)^2}{1}[/tex]

→     [tex]= \frac{25}{1}[/tex]

→     [tex]= 25 \ N[/tex]

Thus the above answer is appropriate.

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