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What is the velocity of a ball swung around on a rope with
radius .25 meters and period .40 seconds? (Write your answer
two significant figures. e.g. : 2.5)
_____meters/seconds

Respuesta :

MathPhys

Answer:

3.9 m/s

Explanation:

The circumference of the circular path is:

C = 2πr

C = 2π (0.25 m)

C = 1.57 m

The speed is therefore:

v = C / t

v = (1.57 m) / (0.40 s)

v = 3.9 m/s

snehashish65

The velocity of ball swinging around the circular path on a rope is 1.4  m/s.

Given data:

The radius of swing is, r = 0.25 m.

The time period of swing is, T = 0.40 s.

In this problem, the ball is tied with rope to make it traverse along a circular path.

The expression for the velocity of ball swinging around the circular path along the rope is given as,

[tex]v = \dfrac{C}{T}[/tex]

Here, C is the circumference traversed by the ball. And its value is,

[tex]C = 2 \pi r\\C = 2 \pi \times0.25\\C =1.570 \;\rm m[/tex]

Solving for velocity as,

[tex]v = \dfrac{0.570}{0.40}\\\\v =1.4 \;\rm m/s[/tex]

Thus, the velocity of ball swinging around the circular path on a rope is 1.4  m/s.

Learn more about the time period around the circular path here:

https://brainly.com/question/11394962

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