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Write a structural formula for the principal organic product formed in the reaction of methyl bromide with NaOH (sodium hydroxide). Click the "draw structure" button to launch the drawing utility.Write a structural formula for the principal organic product formed in the reaction of methyl bromide with NaOH (sodium hydroxide). Click the "draw structure" button to launch the drawing utility.

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Answer:

Methanol is produced as product of the reaction.

Explanation:

Methyl bromide contains a good leaving group [tex]Br^{-}[/tex] because of high polarizability of Br atom and weak C-Br bond.

[tex]OH^{-}[/tex] is a strong base as well as strong nucleophile due to small size and high electronegativity of oxygen atom.

Here methyl bromide primarily acts as an electrophile instead of an acid because of it's very weak acidity.

So, [tex]OH^{-}[/tex] acts as nucleophile towards methyl bromide by replacing bromide ion and forms methanol.

Reaction goes through [tex]S_{N}2[/tex] mechanism.

Structure formula of product has been given below.

Ver imagen OrethaWilkison
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The product of the reaction between NaOH and methyl bromide is methanol.

The reaction between NaOH and methyl bromide is an SN2 reaction. The substrate is the methyl bromide. It is attacked by the OH- ion from the backside leading to inversion of configuration in the product.

The major organic product formed is methanol as the bromide ion is replaced by the hydroxide ion in the nucleophilic substitution reaction. The structure of methanol is shown in the image attached.

Learn more: https://brainly.com/question/8155254

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