Answer:
[tex]J=0.602\ kg-m/s[/tex]
Explanation:
Given that,
Mass of the ball, m = 58 g
To find,
Impulse did she impart to it
Solution,
Let u is the initial speed of the ball. Using equation of kinematics as :
At 5.5 m, v = 0
So, [tex]v^2=u^2+2ah[/tex]
Here, a = -g
[tex]v^2=u^2-2gh[/tex]
[tex]u=\sqrt{2gh}[/tex]
[tex]u=\sqrt{2\times 9.8\times 5.5}[/tex]
u = 10.38 m/s
Since, the ball is stationary just before it is hit, [tex]p_1=0[/tex]
[tex]p_2=mv[/tex]
[tex]p_2=58\times 10^{-3} \times 10.38=0.602\ kg-m/s[/tex]
According to impulse- momentum theorem, the impulse imparted is equal to the change in momentum. So,
[tex]p=0.602\ kg-m/s[/tex]
So, the impulse did impart to it is 0.602 kg-m/s. Hence, this is the required solution.
